((x+5)^2+y^2-a^2)*log(9-x ... 5)^2+y^2-a^2)*(x+y-a+5)=0

Вы ввели

/       2    2    2\    /     2    2\    
\(x + 5)  + y  - a /*log\9 - x  - y / = 0

$$\left(- a^{2} + y^{2} + \left(x + 5\right)^{2}\right) \log{\left (- y^{2} + - x^{2} + 9 \right )} = 0$$

/       2    2    2\                    
\(x + 5)  + y  - a /*(x + y - a + 5) = 0

$$\left(- a^{2} + y^{2} + \left(x + 5\right)^{2}\right) \left(- a + x + y + 5\right) = 0$$

Быстрый ответ

$$a_{1} = - \sqrt{x^{2} + 10 x + y^{2} + 25}$$
=
$$- \sqrt{x^{2} + 10 x + y^{2} + 25}$$
=

-(25 + x^2 + y^2 + 10*x)^0.5

$$a_{2} = \sqrt{x^{2} + 10 x + y^{2} + 25}$$
=
$$\sqrt{x^{2} + 10 x + y^{2} + 25}$$
=

(25 + x^2 + y^2 + 10*x)^0.5

$$x_{3} = -5$$
=
$$-5$$
=

-5

$$a_{3} = y$$
=
$$y$$
=

y

$$y_{4} = 0$$
=
$$0$$
=

0

$$a_{4} = x + 5$$
=
$$x + 5$$
=

5 + x

$$x_{5} = - \sqrt{- y^{2} + 8}$$
=
$$- \sqrt{- y^{2} + 8}$$
=

-(8 - y^2)^0.5

$$a_{5} = y - \sqrt{- y^{2} + 8} + 5$$
=
$$y - \sqrt{- y^{2} + 8} + 5$$
=

5 + y - (8 - y^2)^0.5

$$x_{6} = \sqrt{- y^{2} + 8}$$
=
$$\sqrt{- y^{2} + 8}$$
=

(8 - y^2)^0.5

$$a_{6} = y + \sqrt{- y^{2} + 8} + 5$$
=
$$y + \sqrt{- y^{2} + 8} + 5$$
=

5 + y + (8 - y^2)^0.5