Найду корень уравнения: x^2-2*x*y^2+1=0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-2*y^2)^2 - 4 * (1) * (1) = -4 + 4*y^4
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
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| / 2 2 / / 3 3 4 4 2 2 \\ | / 2 2 / / 3 3 4 4 2 2 \\
2 2 | 4 / / 3 3 \ / 4 4 2 2 \ |atan2\- 4*im (y)*re(y) + 4*re (y)*im(y), -1 + im (y) + re (y) - 6*im (y)*re (y)/| | 4 / / 3 3 \ / 4 4 2 2 \ |atan2\- 4*im (y)*re(y) + 4*re (y)*im(y), -1 + im (y) + re (y) - 6*im (y)*re (y)/|
x1 = re (y) - im (y) + I*|- \/ \- 4*im (y)*re(y) + 4*re (y)*im(y)/ + \-1 + im (y) + re (y) - 6*im (y)*re (y)/ *sin|--------------------------------------------------------------------------------| + 2*im(y)*re(y)| - \/ \- 4*im (y)*re(y) + 4*re (y)*im(y)/ + \-1 + im (y) + re (y) - 6*im (y)*re (y)/ *cos|--------------------------------------------------------------------------------|
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| / 2 2 / / 3 3 4 4 2 2 \\ | / 2 2 / / 3 3 4 4 2 2 \\
2 2 |4 / / 3 3 \ / 4 4 2 2 \ |atan2\- 4*im (y)*re(y) + 4*re (y)*im(y), -1 + im (y) + re (y) - 6*im (y)*re (y)/| | 4 / / 3 3 \ / 4 4 2 2 \ |atan2\- 4*im (y)*re(y) + 4*re (y)*im(y), -1 + im (y) + re (y) - 6*im (y)*re (y)/|
x2 = re (y) - im (y) + I*|\/ \- 4*im (y)*re(y) + 4*re (y)*im(y)/ + \-1 + im (y) + re (y) - 6*im (y)*re (y)/ *sin|--------------------------------------------------------------------------------| + 2*im(y)*re(y)| + \/ \- 4*im (y)*re(y) + 4*re (y)*im(y)/ + \-1 + im (y) + re (y) - 6*im (y)*re (y)/ *cos|--------------------------------------------------------------------------------|
\ \ 2 / / \ 2 /