Подстановка условия
[src](b + 3)/b + (b + 6)/(b + 3) + (b + 9)/(b + 6) + (b + 12)/(b + 9) при b = -1
(b + 3)/b + (b + 6)/(b + 3) + (b + 9)/(b + 6) + (b + 12)/(b + 9)
$$\frac{b + 6}{b + 3} + \frac{1}{b} \left(b + 3\right) + \frac{b + 9}{b + 6} + \frac{b + 12}{b + 9}$$
((-1) + 3)/(-1) + ((-1) + 6)/((-1) + 3) + ((-1) + 9)/((-1) + 6) + ((-1) + 12)/((-1) + 9)
$$\frac{(-1) + 6}{(-1) + 3} + \frac{1}{(-1)} \left((-1) + 3\right) + \frac{(-1) + 9}{(-1) + 6} + \frac{(-1) + 12}{(-1) + 9}$$
(-1 + 3)/(-1) + (-1 + 6)/(-1 + 3) + (-1 + 9)/(-1 + 6) + (-1 + 12)/(-1 + 9)
$$\frac{-1 + 12}{-1 + 9} + \frac{1}{-1} \left(-1 + 3\right) + \frac{-1 + 6}{-1 + 3} + \frac{-1 + 9}{-1 + 6}$$
3 + b 6 + b 9 + b 12 + b
----- + ----- + ----- + ------
b 3 + b 6 + b 9 + b
$$\frac{b + 12}{b + 9} + \frac{b + 9}{b + 6} + \frac{b + 6}{b + 3} + \frac{1}{b} \left(b + 3\right)$$
(3.0 + b)/b + (6.0 + b)/(3.0 + b) + (9.0 + b)/(6.0 + b) + (12.0 + b)/(9.0 + b)
Рациональный знаменатель
[src] / / 2 \ \
(9 + b)*\(6 + b)*\(3 + b) + b*(6 + b)/ + b*(3 + b)*(9 + b)/ + b*(3 + b)*(6 + b)*(12 + b)
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b*(3 + b)*(6 + b)*(9 + b) $$\frac{1}{b \left(b + 3\right) \left(b + 6\right) \left(b + 9\right)} \left(b \left(b + 3\right) \left(b + 6\right) \left(b + 12\right) + \left(b + 9\right) \left(b \left(b + 3\right) \left(b + 9\right) + \left(b + 6\right) \left(b \left(b + 6\right) + \left(b + 3\right)^{2}\right)\right)\right)$$
Объединение рациональных выражений
[src] / / 2 \ \
(9 + b)*\(6 + b)*\(3 + b) + b*(6 + b)/ + b*(3 + b)*(9 + b)/ + b*(3 + b)*(6 + b)*(12 + b)
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b*(3 + b)*(6 + b)*(9 + b) $$\frac{1}{b \left(b + 3\right) \left(b + 6\right) \left(b + 9\right)} \left(b \left(b + 3\right) \left(b + 6\right) \left(b + 12\right) + \left(b + 9\right) \left(b \left(b + 3\right) \left(b + 9\right) + \left(b + 6\right) \left(b \left(b + 6\right) + \left(b + 3\right)^{2}\right)\right)\right)$$
/ 4 3 2 \
2*\243 + 2*b + 42*b + 279*b + 621*b/
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/ 3 2 \
b*\162 + b + 18*b + 99*b/ $$\frac{4 b^{4} + 84 b^{3} + 558 b^{2} + 1242 b + 486}{b \left(b^{3} + 18 b^{2} + 99 b + 162\right)}$$
b + 3 b + 6 b + 9 b + 12
----- + ----- + ----- + ------
b b + 3 b + 6 b + 9
$$\frac{b + 12}{b + 9} + \frac{b + 9}{b + 6} + \frac{b + 6}{b + 3} + \frac{1}{b} \left(b + 3\right)$$
/ 4 3 2 \
2*\243 + 2*b + 42*b + 279*b + 621*b/
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b*(3 + b)*(6 + b)*(9 + b) $$\frac{4 b^{4} + 84 b^{3} + 558 b^{2} + 1242 b + 486}{b \left(b + 3\right) \left(b + 6\right) \left(b + 9\right)}$$
3 2
486 + 12*b + 162*b + 594*b
4 + ----------------------------
4 3 2
b + 18*b + 99*b + 162*b $$\frac{12 b^{3} + 162 b^{2} + 594 b + 486}{b^{4} + 18 b^{3} + 99 b^{2} + 162 b} + 4$$