a+b+c=5 1/a+b+1/b+c+1/c+a=3/2

Вы ввели

a + b + c = 5

$$c + a + b = 5$$

1       1       1          
- + b + - + c + - + a = 3/2
a       b       c          

$$a + c + b + \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{3}{2}$$

Быстрый ответ

$$b_{1} = - \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} + \left(c - 5\right) \left(7 c + 2\right)\right)$$
=
$$- \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} + \left(c - 5\right) \left(7 c + 2\right)\right)$$
=

-((-(2 + 7*c)*(-5 + c)*(10 + 41*c - 7*c^2))^0.5 + (2 + 7*c)*(-5 + c))/(4 + 14*c)

$$a_{1} = \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} - \left(c - 5\right) \left(7 c + 2\right)\right)$$
=
$$\frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} - \left(c - 5\right) \left(7 c + 2\right)\right)$$
=

0.5*((-(2 + 7*c)*(-5 + c)*(10 + 41*c - 7*c^2))^0.5 - (2 + 7*c)*(-5 + c))/(2 + 7*c)

$$b_{2} = \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} - \left(c - 5\right) \left(7 c + 2\right)\right)$$
=
$$\frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} - \left(c - 5\right) \left(7 c + 2\right)\right)$$
=

0.5*((-(2 + 7*c)*(-5 + c)*(10 + 41*c - 7*c^2))^0.5 - (2 + 7*c)*(-5 + c))/(2 + 7*c)

$$a_{2} = - \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} + \left(c - 5\right) \left(7 c + 2\right)\right)$$
=
$$- \frac{1}{14 c + 4} \left(\sqrt{- \left(c - 5\right) \left(7 c + 2\right) \left(- 7 c^{2} + 41 c + 10\right)} + \left(c - 5\right) \left(7 c + 2\right)\right)$$
=

-((-(2 + 7*c)*(-5 + c)*(10 + 41*c - 7*c^2))^0.5 + (2 + 7*c)*(-5 + c))/(4 + 14*c)