x+a*y=a^2 x+b*y=b^2

Вы ввели

           2
x + a*y = a 

$$a y + x = a^{2}$$

           2
x + b*y = b 

$$b y + x = b^{2}$$

Быстрый ответ

$$b_{1} = \frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y - 0.5*(y^2 + 4*x)^0.5

$$a_{1} = \frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y - 0.5*(y^2 + 4*x)^0.5

$$b_{2} = \frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y + 0.5*(y^2 + 4*x)^0.5

$$a_{2} = \frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y - 0.5*(y^2 + 4*x)^0.5

$$b_{3} = \frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} - \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y - 0.5*(y^2 + 4*x)^0.5

$$a_{3} = \frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y + 0.5*(y^2 + 4*x)^0.5

$$b_{4} = \frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y + 0.5*(y^2 + 4*x)^0.5

$$a_{4} = \frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=
$$\frac{y}{2} + \frac{1}{2} \sqrt{4 x + y^{2}}$$
=

0.5*y + 0.5*(y^2 + 4*x)^0.5