x+y=3 x^2+y^2=25
Решение
Быстрый ответ
$$x_{1} = \frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
$$\frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
$$y_{1} = - \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
$$- \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
=
$$\frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
4.70156211871642
$$y_{1} = - \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
$$- \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
-1.70156211871642
$$x_{2} = - \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
$$- \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
$$y_{2} = \frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
$$\frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
=
$$- \frac{\sqrt{41}}{2} + \frac{3}{2}$$
=
-1.70156211871642
$$y_{2} = \frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
$$\frac{3}{2} + \frac{\sqrt{41}}{2}$$
=
4.70156211871642
Численный ответ
[src]
x1 = -1.701562118716424 y1 = 4.701562118716424