Найду корень уравнения: 2x²+3x=0
2 2*x + 3*x = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(3)^2 - 4 * (2) * (0) = 9
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -3/2
x2 = 0
x1 = -1.5
x2 = 0.0