Найду корень уравнения: t^2-1=o
a*t^2 + b*t + c = 0
D = b^2 - 4 * a * c =
(0)^2 - 4 * (1) * (-1 - o) = 4 + 4*o
t1 = (-b + sqrt(D)) / (2*a)
t2 = (-b - sqrt(D)) / (2*a)
_______________________ _______________________
4 / 2 2 /atan2(im(o), 1 + re(o))\ 4 / 2 2 /atan2(im(o), 1 + re(o))\
t1 = - \/ (1 + re(o)) + im (o) *cos|-----------------------| - I*\/ (1 + re(o)) + im (o) *sin|-----------------------|
\ 2 / \ 2 / _______________________ _______________________
4 / 2 2 /atan2(im(o), 1 + re(o))\ 4 / 2 2 /atan2(im(o), 1 + re(o))\
t2 = \/ (1 + re(o)) + im (o) *cos|-----------------------| + I*\/ (1 + re(o)) + im (o) *sin|-----------------------|
\ 2 / \ 2 /