Найду корень уравнения: 3-x^2=0
2 3 - x = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(0)^2 - 4 * (-1) * (3) = 12
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
___ x1 = -\/ 3
___ x2 = \/ 3
x1 = 1.73205080756888
x2 = -1.73205080756888