Найду корень уравнения: x+sqrt(x)=a
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(1 + 2*a)^2 - 4 * (-1) * (-a^2) = (1 + 2*a)^2 - 4*a^2
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
/ ____________________________ \ ____________________________
| 4 / 2 2 /atan2(4*im(a), 1 + 4*re(a))\ | 4 / 2 2 /atan2(4*im(a), 1 + 4*re(a))\
| \/ (1 + 4*re(a)) + 16*im (a) *sin|---------------------------| | \/ (1 + 4*re(a)) + 16*im (a) *cos|---------------------------|
1 | \ 2 / | \ 2 /
x1 = - + I*|- ---------------------------------------------------------------- + im(a)| - ---------------------------------------------------------------- + re(a)
2 \ 2 / 2 / ____________________________ \ ____________________________
|4 / 2 2 /atan2(4*im(a), 1 + 4*re(a))\ | 4 / 2 2 /atan2(4*im(a), 1 + 4*re(a))\
|\/ (1 + 4*re(a)) + 16*im (a) *sin|---------------------------| | \/ (1 + 4*re(a)) + 16*im (a) *cos|---------------------------|
1 | \ 2 / | \ 2 /
x2 = - + I*|---------------------------------------------------------------- + im(a)| + ---------------------------------------------------------------- + re(a)
2 \ 2 / 2