Найду корень уравнения: x^2-10x-75= 0
2 x - 10*x - 75 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-10)^2 - 4 * (1) * (-75) = 400
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -5
x2 = 15
x1 = 15.0
x2 = -5.0