Найду корень уравнения: (x^2)+x+a=0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(1)^2 - 4 * (1) * (a) = 1 - 4*a
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
____________________________ ____________________________
4 / 2 2 /atan2(-4*im(a), 1 - 4*re(a))\ 4 / 2 2 /atan2(-4*im(a), 1 - 4*re(a))\
\/ (1 - 4*re(a)) + 16*im (a) *cos|----------------------------| I*\/ (1 - 4*re(a)) + 16*im (a) *sin|----------------------------|
1 \ 2 / \ 2 /
x1 = - - - ----------------------------------------------------------------- - -------------------------------------------------------------------
2 2 2 ____________________________ ____________________________
4 / 2 2 /atan2(-4*im(a), 1 - 4*re(a))\ 4 / 2 2 /atan2(-4*im(a), 1 - 4*re(a))\
\/ (1 - 4*re(a)) + 16*im (a) *cos|----------------------------| I*\/ (1 - 4*re(a)) + 16*im (a) *sin|----------------------------|
1 \ 2 / \ 2 /
x2 = - - + ----------------------------------------------------------------- + -------------------------------------------------------------------
2 2 2