1 1
/ /
| |
| / 3 \ | / 3\
| sin\x - 1/ dx = | sin\-1 + x / dx
| |
/ /
0 0
$$-{{i\,\Gamma\left({{1}\over{3}} , i\right)\,\sin 1}\over{12}}+{{i\,
\Gamma\left({{1}\over{3}} , -i\right)\,\sin 1}\over{12}}-{{\Gamma
\left({{1}\over{3}} , i\right)\,\cos 1}\over{12}}-{{\Gamma\left({{1
}\over{3}} , -i\right)\,\cos 1}\over{12}}+{{\Gamma\left({{1}\over{3
}}\right)\,\cos 1}\over{6}}$$
Ответ (Неопределённый)
[src]$$-{{\left(i\,\Gamma\left({{1}\over{3}} , i\,x^3\right)-i\,\Gamma
\left({{1}\over{3}} , -i\,x^3\right)\right)\,\sin 1+\left(\Gamma
\left({{1}\over{3}} , i\,x^3\right)+\Gamma\left({{1}\over{3}} , -i\,
x^3\right)\right)\,\cos 1}\over{12}}$$