Найду корень уравнения: (5x-2)(-x+3)=o
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(17)^2 - 4 * (-5) * (-6 - o) = 169 - 20*o
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
________________________________ ________________________________
4 / 2 2 /atan2(-20*im(o), 169 - 20*re(o))\ 4 / 2 2 /atan2(-20*im(o), 169 - 20*re(o))\
\/ (169 - 20*re(o)) + 400*im (o) *cos|--------------------------------| I*\/ (169 - 20*re(o)) + 400*im (o) *sin|--------------------------------|
17 \ 2 / \ 2 /
x1 = -- - ------------------------------------------------------------------------- - ---------------------------------------------------------------------------
10 10 10 ________________________________ ________________________________
4 / 2 2 /atan2(-20*im(o), 169 - 20*re(o))\ 4 / 2 2 /atan2(-20*im(o), 169 - 20*re(o))\
\/ (169 - 20*re(o)) + 400*im (o) *cos|--------------------------------| I*\/ (169 - 20*re(o)) + 400*im (o) *sin|--------------------------------|
17 \ 2 / \ 2 /
x2 = -- + ------------------------------------------------------------------------- + ---------------------------------------------------------------------------
10 10 10