Найду корень уравнения: 2x^2-xy=5
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-y)^2 - 4 * (2) * (-5) = 40 + y^2
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
/ ___________________________________________ \ ___________________________________________
| / 2 / / 2 2 \\| / 2 / / 2 2 \\
| 4 / / 2 2 \ 2 2 |atan2\2*im(y)*re(y), 40 + re (y) - im (y)/|| 4 / / 2 2 \ 2 2 |atan2\2*im(y)*re(y), 40 + re (y) - im (y)/|
| \/ \40 + re (y) - im (y)/ + 4*im (y)*re (y) *sin|------------------------------------------|| \/ \40 + re (y) - im (y)/ + 4*im (y)*re (y) *cos|------------------------------------------|
re(y) |im(y) \ 2 /| \ 2 /
x1 = ----- + I*|----- - -----------------------------------------------------------------------------------------------| - -----------------------------------------------------------------------------------------------
4 \ 4 4 / 4 / ___________________________________________ \ ___________________________________________
| / 2 / / 2 2 \\| / 2 / / 2 2 \\
| 4 / / 2 2 \ 2 2 |atan2\2*im(y)*re(y), 40 + re (y) - im (y)/|| 4 / / 2 2 \ 2 2 |atan2\2*im(y)*re(y), 40 + re (y) - im (y)/|
| \/ \40 + re (y) - im (y)/ + 4*im (y)*re (y) *sin|------------------------------------------|| \/ \40 + re (y) - im (y)/ + 4*im (y)*re (y) *cos|------------------------------------------|
re(y) |im(y) \ 2 /| \ 2 /
x2 = ----- + I*|----- + -----------------------------------------------------------------------------------------------| + -----------------------------------------------------------------------------------------------
4 \ 4 4 / 4