Найду корень уравнения: y=(x-y)^2+1
a*y^2 + b*y + c = 0
D = b^2 - 4 * a * c =
(1 + 2*x)^2 - 4 * (-1) * (-1 - x^2) = -4 + (1 + 2*x)^2 - 4*x^2
y1 = (-b + sqrt(D)) / (2*a)
y2 = (-b - sqrt(D)) / (2*a)
/ _____________________________ \ _____________________________
| 4 / 2 2 /atan2(4*im(x), -3 + 4*re(x))\ | 4 / 2 2 /atan2(4*im(x), -3 + 4*re(x))\
| \/ (-3 + 4*re(x)) + 16*im (x) *sin|----------------------------| | \/ (-3 + 4*re(x)) + 16*im (x) *cos|----------------------------|
1 | \ 2 / | \ 2 /
y1 = - + I*|- ------------------------------------------------------------------ + im(x)| - ------------------------------------------------------------------ + re(x)
2 \ 2 / 2 / _____________________________ \ _____________________________
|4 / 2 2 /atan2(4*im(x), -3 + 4*re(x))\ | 4 / 2 2 /atan2(4*im(x), -3 + 4*re(x))\
|\/ (-3 + 4*re(x)) + 16*im (x) *sin|----------------------------| | \/ (-3 + 4*re(x)) + 16*im (x) *cos|----------------------------|
1 | \ 2 / | \ 2 /
y2 = - + I*|------------------------------------------------------------------ + im(x)| + ------------------------------------------------------------------ + re(x)
2 \ 2 / 2