Найду корень уравнения: x²-2x-8=0
2 x - 2*x - 8 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-2)^2 - 4 * (1) * (-8) = 36
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -2
x2 = 4
x1 = -2.0
x2 = 4.0