Найду корень уравнения: x²-bx+16=0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-b)^2 - 4 * (1) * (16) = -64 + b^2
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
/ ____________________________________________ \ ____________________________________________
| / 2 / / 2 2 \\| / 2 / / 2 2 \\
| 4 / / 2 2 \ 2 2 |atan2\2*im(b)*re(b), -64 + re (b) - im (b)/|| 4 / / 2 2 \ 2 2 |atan2\2*im(b)*re(b), -64 + re (b) - im (b)/|
| \/ \-64 + re (b) - im (b)/ + 4*im (b)*re (b) *sin|-------------------------------------------|| \/ \-64 + re (b) - im (b)/ + 4*im (b)*re (b) *cos|-------------------------------------------|
re(b) |im(b) \ 2 /| \ 2 /
x1 = ----- + I*|----- - -------------------------------------------------------------------------------------------------| - -------------------------------------------------------------------------------------------------
2 \ 2 2 / 2 / ____________________________________________ \ ____________________________________________
| / 2 / / 2 2 \\| / 2 / / 2 2 \\
| 4 / / 2 2 \ 2 2 |atan2\2*im(b)*re(b), -64 + re (b) - im (b)/|| 4 / / 2 2 \ 2 2 |atan2\2*im(b)*re(b), -64 + re (b) - im (b)/|
| \/ \-64 + re (b) - im (b)/ + 4*im (b)*re (b) *sin|-------------------------------------------|| \/ \-64 + re (b) - im (b)/ + 4*im (b)*re (b) *cos|-------------------------------------------|
re(b) |im(b) \ 2 /| \ 2 /
x2 = ----- + I*|----- + -------------------------------------------------------------------------------------------------| + -------------------------------------------------------------------------------------------------
2 \ 2 2 / 2