Найду корень уравнения: 2*x^2 + 3*x - 5= 0
2 2*x + 3*x - 5 = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(3)^2 - 4 * (2) * (-5) = 49
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -5/2
x2 = 1
x1 = -2.5
x2 = 1.0