Найду корень уравнения: 5x^2+12x=0
2 5*x + 12*x = 0
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(12)^2 - 4 * (5) * (0) = 144
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
x1 = -12/5
x2 = 0
x1 = 0.0
x2 = -2.4