Найду корень уравнения: 1/2^(x^2+1)=4^(1-2*x)
сумма
0 + 1 + 3
=
4
произведение
1*1*3
=
3
x1 = 57.75
x2 = 19.75
x3 = 91.75
x4 = 15.7500000000105
x5 = 33.75
x6 = 47.75
x7 = 39.75
x8 = 85.75
x9 = 25.75
x10 = 69.75
x11 = 83.75
x12 = 97.75
x13 = 71.75
x14 = 45.75
x15 = 31.75
x16 = 93.75
x17 = 61.75
x18 = 103.75
x19 = 3.0
x20 = 29.75
x21 = 17.75
x22 = 87.75
x23 = 81.75
x24 = 99.75
x25 = 89.75
x26 = 21.75
x27 = 1.0
x28 = 67.75
x29 = 59.75
x30 = 11.8000948647943
x31 = 73.75
x32 = 55.75
x33 = 43.75
x34 = 95.75
x35 = 63.75
x36 = 23.75
x37 = 77.75
x38 = 41.75
x39 = 49.75
x40 = 35.75
x41 = 107.75
x42 = 105.75
x43 = 51.75
x44 = 27.75
x45 = 79.75
x46 = 101.75
x47 = 75.75
x48 = 37.75
x49 = 53.75
x50 = 65.75
x51 = 13.7500110072894
![Решите уравнение 1/2^(x^2+1)=4^(1-2*x) (1 делить на 2 в степени (х в квадрате плюс 1) равно 4 в степени (1 минус 2 умножить на х)) - Найдите корень уравнения подробно по-шагам. [Есть ответ!] 1/2^(x^2+1)=4^(1-2*x) (уравнение) /media/krcore-image-pods/hash/equation/6/de/e9c7aff5b52fb328141a7474c799a.png](/media/krcore-image-pods/hash/equation/6/de/e9c7aff5b52fb328141a7474c799a.png)