Найду корень уравнения: x=sqrt(a)
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4 / 2 2 /atan2(im(a), re(a))\ 4 / 2 2 /atan2(im(a), re(a))\
x1 = \/ im (a) + re (a) *cos|-------------------| + I*\/ im (a) + re (a) *sin|-------------------|
\ 2 / \ 2 /сумма
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4 / 2 2 /atan2(im(a), re(a))\ 4 / 2 2 /atan2(im(a), re(a))\
\/ im (a) + re (a) *cos|-------------------| + I*\/ im (a) + re (a) *sin|-------------------|
\ 2 / \ 2 /=
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4 / 2 2 /atan2(im(a), re(a))\ 4 / 2 2 /atan2(im(a), re(a))\
\/ im (a) + re (a) *cos|-------------------| + I*\/ im (a) + re (a) *sin|-------------------|
\ 2 / \ 2 /произведение
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4 / 2 2 /atan2(im(a), re(a))\ 4 / 2 2 /atan2(im(a), re(a))\
\/ im (a) + re (a) *cos|-------------------| + I*\/ im (a) + re (a) *sin|-------------------|
\ 2 / \ 2 /=
I*atan2(im(a), re(a)) _________________ --------------------- 4 / 2 2 2 \/ im (a) + re (a) *e