Найду корень уравнения: cos(pi*(x+1)/4)=sqrt(2)/2
___ /pi*(x + 1)\ \/ 2 cos|----------| = ----- \ 4 / 2
сумма
0 + 0 + 6
=
6
произведение
1*0*6
=
0
x1 = -90.0
x2 = -64.0
x3 = 46.0
x4 = 32.0
x5 = 22.0
x6 = 30.0
x7 = -58.0
x8 = -16.0
x9 = 48.0
x10 = 38.0
x11 = 78.0
x12 = 70.0
x13 = 24.0
x14 = -72.0
x15 = -80.0
x16 = 6.0
x17 = 40.0
x18 = 80.0
x19 = 14.0
x20 = -2.0
x21 = -18.0
x22 = 86.0
x23 = -74.0
x24 = 94.0
x25 = 62.0
x26 = -50.0
x27 = 0.0
x28 = -26.0
x29 = -34.0
x30 = -48.0
x31 = -82.0
x32 = 54.0
x33 = -66.0
x34 = -10.0
x35 = -40.0
x36 = 8.0
x37 = 88.0
x38 = -96.0
x39 = 102.0
x40 = -8.0
x41 = -24.0
x42 = 96.0
x43 = 56.0
x44 = -56.0
x45 = 16.0
x46 = 64.0
x47 = -42.0
x48 = -88.0
x49 = 72.0
x50 = -32.0
x51 = -98.0
![Решите уравнение cos(pi*(x+1)/4)=sqrt(2)/2 (косинус от (число пи умножить на (х плюс 1) делить на 4) равно квадратный корень из (2) делить на 2) - Найдите корень уравнения подробно по-шагам. [Есть ответ!] cos(pi*(x+1)/4)=sqrt(2)/2 (уравнение) /media/krcore-image-pods/hash/equation/4/97/2439eec53c2a9a0325c361eadb26f.png](/media/krcore-image-pods/hash/equation/4/97/2439eec53c2a9a0325c361eadb26f.png)