Найду корень уравнения: sin(-x/3)=sqrt(2)/2
Разделим обе части ур-ния на -1
сумма
3*pi 15*pi 0 - ---- + ----- 4 4
=
3*pi
произведение
-3*pi 15*pi 1*-----*----- 4 4
=
2 -45*pi ------- 16
x1 = 539.568538254047
x2 = -96.6039740978861
x3 = 11.7809724509617
x4 = -21.2057504117311
x5 = 91.8915851175014
x6 = -63.6172512351933
x7 = 49.4800842940392
x8 = -44.7676953136546
x9 = 68.329640215578
x10 = -3305.74086973986
x11 = -134.303085940964
x12 = -40.0553063332699
x13 = -82.4668071567321
x14 = 1142.75432774329
x15 = -1703.52861640907
x16 = -25.9181393921158
x17 = 16.4933614313464
x18 = 35.3429173528852
x19 = 54.1924732744239
x20 = 2179.47990342792
x21 = -77.7544181763474
x22 = -58.9048622548086
x23 = -101.316363078271
x24 = -7.06858347057703
x25 = -2.35619449019234
x26 = 87.1791961371168
x27 = 13376.1161208219
x28 = 73.0420291959627
x29 = -473.595092528661
x30 = 30.6305283725005
x31 = 256.825199430966