Подстановка условия
[src](1 + x^2 + x^3)^6 при x = 1/4
$$\left(x^{3} + x^{2} + 1\right)^{6}$$
(1 + (1/4)^2 + (1/4)^3)^6
$$\left((1/4)^{3} + (1/4)^{2} + 1\right)^{6}$$
(1 + (1/4)^2 + (1/4)^3)^6
$$\left(\left(\frac{1}{4}\right)^{3} + \left(\frac{1}{4}\right)^{2} + 1\right)^{6}$$
$$\frac{107918163081}{68719476736}$$
18 2 3 17 4 16 15 5 6 14 7 13 8 12 9 11 10
1 + x + 6*x + 6*x + 6*x + 15*x + 15*x + 26*x + 30*x + 35*x + 45*x + 60*x + 66*x + 75*x + 76*x + 80*x + 90*x + 96*x
$$x^{18} + 6 x^{17} + 15 x^{16} + 26 x^{15} + 45 x^{14} + 66 x^{13} + 76 x^{12} + 90 x^{11} + 96 x^{10} + 80 x^{9} + 75 x^{8} + 60 x^{7} + 35 x^{6} + 30 x^{5} + 15 x^{4} + 6 x^{3} + 6 x^{2} + 1$$